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The equation of SHM of a particle is `(d^2y)/(dt^2)+ky=0`, where k is a positive constant. The time period of motion isA. `(2pi)/(sqrt3)`B. `(2pi)/(k)`C. `k/2`D. `(sqrtk)/(2pi)` |
Answer» Correct Answer - A `(d^2y)/(dt^2)=-ky=-omega^2y` `omega=sqrtk` `T=(2pi)/(sqrtk)` |
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