1.

The equation of standing wave of the second resonance can be ,

Answer»

`P_(EX) = 2A sin 2pi (y = 1cm) cos 2pi 9340)t`
`P_(ex) = 2A sin 2pi (y = 1cm) cos 2pi 9340)t`
`P_(ex) = 2A sin 2pi (y = 1cm) cos 2pi 9340)t`
`P_(ex) = 2A sin 2pi (y = 1cm) cos 2pi 9340)t`

Solution :`k = (2pi0/(lambda) = (2pi)/(1) = 2pi omega = 2pif = (2pi) (340)`
FIRST NODE will be formed at `y = -1` instead of `y =0` so eqn of standing wave is `P_(ex) = 2A sin 2pi (y + 1cm) cos 2pi (340)t` .


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