InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The equation of the bisector of that angle between the lines x + y = 3 and 2x - y = 2 which contains the point (1,1) isA. `(sqrt5 - 2sqrt2) x + (sqrt5 + sqrt2) y - 3sqrt5 + 2 sqrt2 = 0`B. `(sqrt5 + 2sqrt2) x + (sqrt5 - sqrt2)y - 3sqrt5 - 2 sqrt2 = 0`C. 3x = 10D. none of these |
|
Answer» Correct Answer - A First we re-write the equations of the two lines in such a way that the values of the expressions on the left hand sides of the equality for x = 1 , y = 1 become positive . Re-writing the given equations , we obtain -x-y + 3 = 0 and - 2x + y + 2 = 0. Now , we obtain the bisector of the angle containing point (1,1) for positive sign. The required bisector is given by `(-x-y + 3)/(sqrt((-1)^(2) + (-1)^(2))) = + (-2 x + y + 2)/(sqrt(-2)^(2) + 1^(2))` `implies (sqrt5 - 2 sqrt2 ) x + (sqrt5 + sqrt2)y - 3sqrt5 + 2sqrt2 = 0` . |
|