

InterviewSolution
Saved Bookmarks
1. |
The equation of the bisector of the acute angle between the lines `2x-y+4=0`and `x-2y=1`is`x-y+5=0``x-y+1=0``x-y=5`(d) none oftheseA. `x + y+ 5=0`B. `x-y+ 1=0`C. ` x- y - 5=0`D. none of these |
Answer» Correct Answer - B The equations of the lines are `2x - y + 5 =0` We have , `2x -1+(-1) xx 2 le 0 ` i.e, `a_(1)a_(2) +b_(1)b_(2) lt 0` Therefore, the equation of the bisector of acute angle is `(2x-y+4)/(sqrt(1+4)) = (-x+2y+1)/(sqrt((-1)^(2)+2^(2)))` `rArr 2x - y + 4 = - x + 2y + 1` `rArr 3x -3y + 3 = 0 rArr x -y + 1 =0` |
|