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The equation of the diagonal of the square formed by the pairs of lines `xy +4x - 3y - 12 = 0` and `xy - 3x +4 y - 12 = 0` isA. `x - y = 0`B. `x +y +1 = 0`C. `x +y = 0`D. `x - y +1 = 0` |
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Answer» Correct Answer - A::B `xy +4x -3y -12 =0` `rArr (x-3) (y+4) =0` `xy -3x +4y -12 =0` `rArr (x-4) (y-3) =0` The vertices are `A =(-4,-4), B =(-4,3), C =(3,3), D =(3,-4)` Diagonal AC is `x =y` and diagonal BD is `x +y +1 = 0`. |
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