The equation of the line AB is `y = x`. If A and B lie on the same side of the line mirror `2x-y = 1`, then the equation of the image of AB is(a) `x+y-2=0`(b) `8x+y-9=0`(c) `7x-y-6=0`(d) `None of theseA. x + y - 2 = 0B. 8x + y - 9 = 0C. 7x - y - 6 = 0D. none of these

The equation of the line AB is `y = x`. If A and B lie on the same sid

1.	The equation of the line AB is `y = x`. If A and B lie on the same side of the line mirror `2x-y = 1`, then the equation of the image of AB is(a) `x+y-2=0`(b) `8x+y-9=0`(c) `7x-y-6=0`(d) `None of theseA. x + y - 2 = 0B. 8x + y - 9 = 0C. 7x - y - 6 = 0D. none of these
Answer» The required line is the line passing through the intersection of two lines and the image of a point on the line y = x in the line mirror 2x - y =1 Given lines intersect at (1,1) The image of (0,0) in the mirror 2x - y = 1 is given by `(x - 0)/(2) = (y-0)/(-1) -2 ((2 xx 0 -0-0 -1)/(4+ 1))` `implies x = (4)/(5) , y = (-2)/(5)` Thus , the required line passing through (1,1) and `((4)/(5) , (-2)/(5))` So , its equation is `y - 1 = ((-2)/(5) - 1)/((4)/(5) - 1) (x - 1)` `implies y - 1 = 7 (x -1) implies 7x - y - 6 = 0`

Discussion

No Comment Found

Related InterviewSolutions

Find the ratio in which the x-axis cuts the join of the points A(4,5) and B(-10,-2). Also, find the point of intersection.
If the origin is shifted to the point (-3,-2) by a translation of the axes, find the new coordinates of the point (3,-5).
The distance between the lines `5x-12y+65=0` and `5x-12y-39 = 0` is :A. 4B. 16C. 2D. 8
Prove that the locus of the centroid of the triangle whose vertices are`(acost ,asint),(bsint ,-bcost),`and `(1,0)`, where `t`is a parameter, is circle.A. `(3x -1)^(2) + (3y)^(2) = a^(2) - b^(2)`B. `(3x -1)^(2) + (3y)^(2) = a^(2) + b^(2)`C. `(3x + 1)^(2) + (3y)^(2) = a^(2) + b^(2)`D. ` (3x + 1)^(2) + (3y)^(2) = a^(2) - b^(2)`
Prove that the locus of the centroid of the triangle whose vertices are`(acost ,asint),(bsint ,-bcost),`and `(1,0)`, where `t`is a parameter, is circle.A. `(3x+1)^(2) + (3y)^(2) = a^(2) - b^(2)`B. `(3x - 1)^(2) = a^(2) - b^(2)`C. `(3x -1)^(2) + (3y)^(2) = a^(2) + b^(2)`D. `(3x + 1)^(2) + (3y)^(2) = a^(2) + b^(2)`
For `a gt b gt c gt 0`, if the distance between `(1,1)` and the point of intersection of the line `ax+by-c=0` and `bx+ay+c=0` is less than `2sqrt2` then,(A) `a+b-cgt0` (B) `a-b+clt0` (C) `a-b+cgt0` (D) `a+b-clt0`A. `a+b-c gt 0`B. `a-b+c lt 0`C. `a-b+c gt0`D. `a+b-c lt 0`
ABC is a triangle formed by the lines xy = 0 and x + y = 1 . Statement - 1 : Orthocentre of the triangle ABC is at the origin . Statement - 2 : Circumcentre of `Delta`ABC is at the point (1/2 , 1/2) .A. Statement -1 is True , Statement - 2 is true , Statement- 2 is a correct explanation for statement - 12B. Statement-1 is True , Statement-2 is True , Statement -2 is not a correct explanation for Statement - 1 .C. Statement-1 is True , Statement - 2 is False .D. Statement - 1 is False , Statement -2 is True .
Find the equations of the altitudes of a `triangle ABC`, whose vertices are A(2,-2), B(1,1) and C(-1,0).
The orthocentre of the triangle formed by the lines `x=2,y=3` and `3x+2y=6` is at the pointA. (2,0)B. (0,3)C. (2,3)D. none of these
If A(0, 0), B(2, 4) and C(6, 4) are the vertices of a `triangle ABC`, find the equations of its sides.

The equation of the line AB is `y = x`. If A and B lie on the same side of the line mirror `2x-y = 1`, then the equation of the image of AB is(a) `x+y-2=0`(b) `8x+y-9=0`(c) `7x-y-6=0`(d) `None of theseA. x + y - 2 = 0B. 8x + y - 9 = 0C. 7x - y - 6 = 0D. none of these

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment