InterviewSolution
Saved Bookmarks
| 1. |
The equation of the line passing through the center and bisecting thechord `7x+y-1=0`of the ellipse `(x^2)/1+(y^2)/7=1`isA. x=yB. 2x=yC. x=2yD. x+y=0 |
|
Answer» Let (h,k) be the midpoint of the chord 7x+y-1=0. Then, `(hx)/(1)+(ky)/(7)=(h^(2))/(1)+(k^(2))/(7)" "(1)` and `7x+y=1 " "(2)` represent the same straight line. Therefore, `(h)/(7)=(k)/(7) or h=k` Thus, the equation of the line joining (0,0) adn (h,k) is ty-x=0 |
|