1.

The equation of the normal to the curve y = -√x + 2 at the point of its intersection with the bisector of the first quadrant is : (A)   2x – y + 1 = 0(B)   4x – y + 16 = 0 (C)  4x – y = 16 (D)  2x – y – 1 = 0

Answer»

Correct option  (D) 2x – y – 1 = 0

Explanation:

The point of intersection of the curve y = x + 2  with the bisector of the first quadrant i.e. y = x is (1,1) {Neglect the point (4,0) as it does not satisfy y = x}. Equation of normal to the curve at (1,1) is 2x - y = 1.



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