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The equation of the normal to the curve y = -√x + 2 at the point of its intersection with the bisector of the first quadrant is : (A) 2x – y + 1 = 0(B) 4x – y + 16 = 0 (C) 4x – y = 16 (D) 2x – y – 1 = 0 |
Answer» Correct option (D) 2x – y – 1 = 0 Explanation: The point of intersection of the curve y = √x + 2 with the bisector of the first quadrant i.e. y = x is (1,1) {Neglect the point (4,0) as it does not satisfy y = x}. Equation of normal to the curve at (1,1) is 2x - y = 1. |
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