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The equation of the plane through the point (1,2,3) and parallel to the plane `x+2y+5z=0` isA. `(x-1)+2(y-2)+5(z-3)=0`B. `x+2y+5z=14`C. `x+2y+5z=6`D. none of these |
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Answer» Correct Answer - A Required planeis parallel to the palne `x+2y+5z=0`.Therefore direction of a vector normal to the plane are proportional to 1,2,5. Hence the equation of the required plane is `(x-1)+2(y-2)+5(z-3)=0` |
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