The equation of the plane which bisects the line joining `(2, 3, 4)` and `(6,7,8)`A. `x+y+z+15=0`B. `x-y-z-15=0`C. `x-y+z-15=0`D. `x+y+z-15=0`

The equation of the plane which bisects the line joining `(2, 3, 4)` a

1.	The equation of the plane which bisects the line joining `(2, 3, 4)` and `(6,7,8)`A. `x+y+z+15=0`B. `x-y-z-15=0`C. `x-y+z-15=0`D. `x+y+z-15=0`
Answer» Correct Answer - D Let the two points be `P(2,3,4)` and `Q(6,7,8)` and let `R` be their mid-point. The required plane passes through the mid point `R` and is normal to `PQ`. So, its equation is `[(vecr.(4hati+5hatj+6hatk)].(4hati+4hatj+4hatk)=0` `impliesvecr.(hati+hatj+hatk)-(4+5+6)=0impliesx+y+z-15=0`

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