InterviewSolution
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InterviewSolution
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The equation of the planewhich is equally inclined to the lines `(x-1)/2=y/(-2)=(z+2)/(-1)a n d=(x+3)/8=(y-4)/1=z/(-4)`and passing through the origin is/area. `14 x-5y-7z=0`b. `2x+7y-z=0`c. `3x-4y-z=0`d. `x+2y-5z=0`A. `14x-5y-7z=0`B. `2x+7y-z=0`C. `3x-4y-z=0`D. `x+2y-5z=0` |
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Answer» Correct Answer - a, b The plane is equaly inclined to the lines. Hence, it is perpendicular to the angle bisector of the vectors `2hati-2hatj-hatk and 8hati+hatj-4hatk`. Vector along the angle bisectors of the vectors are `" "(2hati-2hatj-hatk)/(3) pm (8hati+hatj-4hatk)/(9)` or `" "(14hati-5hatj-7hatk)/(9) and (-2hati-7hatj+hatk)/(9)` Hence, the equations of the planes are `" "14x-5y-7z=0 or 2x+7y-z=0` |
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