InterviewSolution
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InterviewSolution
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The equation of the straight line passing through the point `(4. 3)` and making intercepts on the co ordinate axes whose sum is ` -1`, isA. `(x)/(2) - (y)/(3) = 1 ` and `(x)/(-2) + (y)/(1) = 1`B. `(x)/(2) - (y)/(3) = -1` and `(x)/(-2) + (y)/(1) = -1`C. `(x)/(2) + (y)/(3) = 1` and `(x)/(2) + (y)/(1) = 1`D. `(x)/(2) + (y)/(3) = -1` and `(x)/(-2) + (y)/(1) = -1` |
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Answer» Correct Answer - A Let the equation of the line be `(x)/(a) + (y)/(b)=1 " " … (i)` It passses through (4,3) `therefore (4)/(a) + (3)/(b) = 1 " " … (ii)` It is given that a + b = - 1 `" " … (iii)` Solving these equations , we get (a =- 2 , b = 1) or , (a = 2 , b = -3) Substituting the value of a and b in (i) , we get `(x)/(-2) + (y)/(1) = 1` and `(x)/(2) + (y)/(-3) = 1` ALTER Clearly , lines in option (a) pass through (4,3) and the sum of their intercepts on the coordinates axes is -1 . Hence , option (a) is correct . |
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