1.

The equation of the tangent to the curve `y""=""x""+4/(x^2)`, that is parallel to thex-axis, is(1) `y""=""1`(2) `y""=""2`(3) `y""=""3`(4) `y""=""0`A. `y=2`B. `y=3`C. `y=0`D. `y=1`

Answer» Correct Answer - B
Let `(x_(1),y_(1))` be a point on the curve `y=x+(4)/(x^(2))` where tangent is parallel to x-axis. Then,
`((dy)/(dx))_((x_(1)","y_(1)))=0 rArr 1-(8)/(x_(1)^(3)) =0 rArr x_(1)=2 `
` therefore y_(1)=x_(1)+(4)/(x_(1)^(2))rArr y_(1)=3 `
The equation of the required tangent is
`y-3=0(x-2) " or, " y=3 `


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