1.

The equation of wave on a string of linear mass density 0.04 kg m^(-1)is given by y = 0.02 (m) sin [ 2 pi ( (t)/(0.04(s)) - (x)/(0.50(m)) ) ] The tension in the string is :

Answer»

6.25 N
4.0 N
12.5 N
0.5 N

Solution :` v_(2) sqrt((T)/(mu)) or t = V^(2) mu`
from GIVEN EQUATION v = `(50)/(4) = ((25)/(2)) ms^(-1)`
`therefore "" T = (625)/(4) xx 0.04 ` = 6.25 N
so CORRECT choice is (a).


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