1.

The equation to the locus of a point which is always equidistant from the points (1, 0) and (0, -2) is :A. `2x+4y+3=0`B. `4x+2y+3=0`C. `2x+4y-3=0`D. `4x+2y-3=0`

Answer» Correct Answer - A
Let P(x, y) be the point.
Let `A=(1, 0)` and `B=(0, -2)` then
`PA=PB`
`implies (PA)^(2)=(PB)^(2)`.
`implies (x-1)^(2)+y^(2)=x^(2)+(y+2)^(2)`.
`implies 1-2x=4y+4`
`implies 2x+4y+3=0`


Discussion

No Comment Found

Related InterviewSolutions