The equation `x^2 - 3xy+ lambday^2 + 3x - 5y + 2 = 0` where `lambda` is a real number, represents a pair of straight lines. If `theta` is the angle between the lines, then `cosec^2theta =`A. 2B. 0C. 3D. 1

The equation `x^2 - 3xy+ lambday^2 + 3x - 5y + 2 = 0` where `lambda` i

1.	The equation `x^2 - 3xy+ lambday^2 + 3x - 5y + 2 = 0` where `lambda` is a real number, represents a pair of straight lines. If `theta` is the angle between the lines, then `cosec^2theta =`A. 2B. 0C. 3D. 1
Answer» Correct Answer - B We have, `x^(2)-3xy+lambda y^(2)+3x-5y+2=0` Here, `a=1, b=lambda,c=2, h=-3//2,g=3//2 and f=-5//2` We have, `tan(tan^(-1)3)=(2sqrt((9)/(4)-lambda))/(1+lambda)` `rArr" "3=(sqrt(9-4lambda))/(a+lambda)` `rArr" "9(lambda+1)^(2)=9-4lambda` `rArr" "9lambda^(2)+22lambda=0rArr lambda=0,-(22)/(9)rArr lambda=0" "[because lambda ge 0]`

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