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The equilibrium constant expression for the equilibrium `2NH_(3)(g) + 2O_(2)(g)hArrN_(2)O(g) + 3H_(2)O(g)` isA. `K_(C) =([N_(2)O][H_(2)O]^(3))/([NH_(3)][O_(2)])`B. `K_(C) =([H_(2)O]^(3) [N_(2)O])/([NH_(3)]^(2) [O_(2)]^(2))`C. `K_(C) =([NH_(3)]^(2))/([N_(2)O][H_(2)O]^(3))`D. `K_(C) =([NH_(3)][O_(2)])/([N_(2)O][H_(2)O])` |
Answer» Correct Answer - B `2NH_(3)(g) + 2O_(2)(g)hArrN_(2)O(g) + 3H_(2)O(g)` `K_(C) = ((N_(2)O)xx(H_(2)O)^(3))/((NH_(3))^(2)xx(O_(2))^(2))` |
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