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The equilibrium constant for a reaction is `10`. What will be the value of `DeltaG^(Θ)`? `R=8.314 J K^(-1) mol^(-1), T=300 K`.A. `-5527 kJ mol^(-1)`B. `-5.527 kJ mol^(-1)`C. `-55.27 kJ mol^(-1)`D. `+5.527 kJ mol^(-1)` |
Answer» Correct Answer - B `DeltaG^(@)=-RT ln K = -2.303 RT log K` `=-2.303xx8xx300=-5527 J mol^(-1)` `=-5.527 kJ mol^(-1)` |
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