InterviewSolution
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InterviewSolution
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The equilibrium constant for the given reaction: `SO_(3(g))hArrSO_(2(g))+1//2O_(2(g))`, `(K_(c)=4.9xx10^(-2))` The value of `K_(c)` for the reaction: `2SO_(2(g))+O_(2(g))hArr2SO_(3(g))`, will be :A. `416`B. `2.40xx10^(-3)`C. `9.8xx10^(-2)`D. `4.9xx10^(-2)` |
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Answer» `K_(c_(1))=([SO_(2)][O_(2)]^(1//2))/([SO_(3)])=4.9xx10^(-2)` `K_(c_(2))=([SO_(3)]^(2))/([SO_(2)]^(2)[O_(2)])=[(1)/(K_(c_(1)))]^(2)=[(1)/(4.9xx10^(-2))]^(2)` `=416.5` |
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