1.

The equilibrium constant for the reaction: `CH_(3)COOH(l) +C_(2)H_(5)OH(l) hArr CH_(3)COOC_(2)H_(5)(l)+H_(2)O(l)` has been found to be equal to `4` at `25^(@)C`. Calculate the free energy change for the reaction.

Answer» `DeltaG^(Theta) =- 2.303 xx 8.314 xx 298 log 4`
`=- 3.435 kJ mol^(-1)`


Discussion

No Comment Found

Related InterviewSolutions