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The equilibrium constant for the reaction: `CH_(3)COOH(l) +C_(2)H_(5)OH(l) hArr CH_(3)COOC_(2)H_(5)(l)+H_(2)O(l)` has been found to be equal to `4` at `25^(@)C`. Calculate the free energy change for the reaction. |
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Answer» `DeltaG^(Theta) =- 2.303 xx 8.314 xx 298 log 4` `=- 3.435 kJ mol^(-1)` |
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