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The equilibrium constant for the reaction `CO_(2)(g) +H_(2)(g) hArr CO(g) +H_(2)O(g) at 298 K` is `73`. Calculate the value of the standard free enegry change `(R =8.314 J K^(-1)mol^(-1))` |
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Answer» We know, `DeltaG^(Theta) =- 2.303 RT log K_(c)` Given, `K_(c) = 70, R = 8.314 J K^(-1) mol^(-1), T = 298 K` Therefore, form the above equation `DeltaG^(Theta) = - 2.303 xx 8.314 xx 298 log_(10)70 =- 10527 kJ` |
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