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The equilibrium constant `K_(c)` for the reaction, `2NaHCO_(3)(s)hArrNa_(2)CO_(3)(s)+CO_(2)(g)+H_(2)O(g)`A. `K_(c)=([Na_(2)CO_(3)][CO_(2)][H_(2)O])/([NaHCO_(3)]^(2))`B. `K_(c)=([Na_(2)CO_(3)])/([NaHCO_(3)]^(2))`C. `K_(c)=[CO_(2)][H_(2)O]`D. `K_(c)=P_(CO_(2)x)xxP_(H_(2)O` |
Answer» Correct Answer - A | |