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The equilibrium constant `K_(c)` for the reaction `SO_(2)(g)+NO_(2)(g)hArrSO_(3)(g)+NO(g) ` is 16. If one mole of all four gases is taken in a one litre container, the equilibrium concentration of `SO_(3)` would beA. `0.4m`B. `0.6m`C. `1.4m`D. `1.6m` |
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Answer» Correct Answer - D Given `SO_(2(g))+NO_(2(g))to SO_(3(g))+NO_((g))` `{:("At initial concentration", "1 mole", "1 mole", "1 mole", "1 mole"),("At equlibrium concentration","1-x mole","1-x mole", "1+ mole", "1+ mole"):}` Applying law of mass action, `K_(c)=([SO_(3)][NO])/([SO_(2)][NO_(2)])=((1+x)(1+x))/((1-x)(1-x))=16` `or ((1+x)^(2))/((1-x)^(2))=16or(1+x)/(1-x)=4` `1+x=4-4x` `5x=3, i.e.,x=3//5=0.6` `"conc. of" SO_(3) "at equlibrium"=1+x=1+0.6=1.6"mole"` |
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