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The equilibrium constant `(K)` for the reaction. `A+2BhArr2C+D` is:A. `([C]^(2)[D])/([A][2B])`,B. `([2C][D])/([A][2B])`C. `([C][D])/([A][B])`D. `([C]^(2)[D])/([A][B]^(2))` |
Answer» Correct Answer - D | |