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The equilibrium constant (K) for the reaction `Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s)`, will be [Given, `E_(cell)^(@)=0.46 V`]A. `3.9xx10^(15)`B. `3.9xx10^(10)`C. `1.9xx10^(15)`D. `1.9xx10^(9)` |
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Answer» Correct Answer - A `E_(cell)=0rArrE_(cell)^(@)=(0.059)/(2)logK` `rArr logK=15.6rArrK=10^(15.6)=3.9xx10^(15)` |
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