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The equilibrium constant `K_(p)` for a homogeneous gaseous reaction is `10^(-8)`. The standard Gibbs free energy change `DeltaG^(ɵ)` for the reaction `("using" R=2 cal K^(-1) mol^(-1))` isA. `10.98 kcal`B. `-1.9 kcal`C. `-4.1454 kcal`D. `+4.1454 kcal` |
Answer» Correct Answer - A `DeltaG^(ɵ)=-2.303 RT log K` `=-2.303xx2xx298 log 10^(-8)` `=-2.303xx2xx298xx-8 cal` `=10980 cal=10.98 kcal` |
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