

InterviewSolution
Saved Bookmarks
1. |
The equilibrium constant `K_(p)` for the homogeneous reaction is `10^(-3)`. The standard Gibbs free energy change `DeltaG^(ɵ)` for the reaction at `27^(@)C ("using" R=2 cal K^(-1) mol^(-1))` isA. ZeroB. `-1.8 kcal`C. `-4.154 kal`D. `+4.154 kcal` |
Answer» Correct Answer - D `DeltaG^(ɵ)=-RT "In" K_(p)` `=-2xx300xxIn (10^(-3))` `=+4.154 kcal` |
|