1.

The equilibrium constant of a reaction is `20.0`. At equilibrium, the reate constant of forward reaction is `10.0`. The rate constant for backward reaction is :A. `0.5`B. `2.0`C. `10.0`D. `200.0`

Answer» `K_(c)=(K_(f))/(K_(b))`
`:. 20=(10)/(K_(b))`, `:. K_(b)=(1)/(2)=0.5`


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