InterviewSolution
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InterviewSolution
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The equilibrium constant of the reaction `2C_(3) H_(6)(g)iffC_(2)H_(4)(g) + C_(4)H_(8)(g)` is found to fit the expression `InK_(eq)= - 1.04-(1088)/(T//K)` (where T/k is temperature expressed in Kelvin scale ) Calculate the standard reaction enthalpy and entrophy at 400 K. |
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Answer» Correct Answer - `DeltaH^(@)= 9.04 kJ//mol; DeltaS^(@) = - 8.64J//mol^(-1)K^(-1)` `DeltaG^(@)= DeltaH ^(@)- TDeltaS^(@)` `DeltaG^(@) = -RT In K` `- RT In K = DeltaH^(@)- TDeltaS^(@)` `In K = - (DeltaH^(@))/(RT) + (T DeltaS^(@))/(RT)` `(1088)/(T)= (DeltaH^(@))/(RT)` `DeltaH^(@) = 9.045 KJ` `(DeltaS^(@))/(R)= - 1.04` `DeltaS^(@) = -8.64 J mol^(-1) K^(-1)` |
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