The equilibrium constant of the reaction `H_(2)(g)+I_(2)(g)hArr2HI(g)` at `426^(@)C` is `55.3`, what will be the value of equilibrium constant a. if the reaction is reversed and b. if the given reaction is represented as `3H_(2)+3I_(2)hArr6HI`?

The equilibrium constant of the reaction `H_(2)(g)+I_(2)(g)hArr2HI(g)`

1.	The equilibrium constant of the reaction `H_(2)(g)+I_(2)(g)hArr2HI(g)` at `426^(@)C` is `55.3`, what will be the value of equilibrium constant a. if the reaction is reversed and b. if the given reaction is represented as `3H_(2)+3I_(2)hArr6HI`?
Answer» The reverse reaction of the given reaction is `2HIhArrH_(2)+I_(2)` :. Equilibrium constant `=1/55.3` b. The reaction `3H_(2)+3I_(2)hArr6HI` has been obtained by multiplying the reaction, `H_(2)I_(2)hArr2HI` by `3`, hence, `K=(55.3)^(3)`

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