The equilibrium constant of the reactionCO2 (g) + H2 (g) ⇌ CO (g) +

1.	The equilibrium constant of the reactionCO2 (g) + H2 (g) ⇌ CO (g) + H2O (g) at 298 K is 73. Calculate the value of the standard free energy change, (Q = 8.314 J mol-1 K-1).
Answer» ΔG° = -2.303 RT log K_C = -2.303 x (8.314 mol^-1 K^-1) x 298 K x log 73 = -2.303 x 8.314 x 298 x 1.8633 = -10632 J = -10.632 kJ

The equilibrium constant of the reactionCO2 (g) + H2 (g) ⇌ CO (g) + H2O (g) at 298 K is 73. Calculate the value of the standard free energy change, (Q = 8.314 J mol-1 K-1).

Answer»

ΔG° = -2.303 RT log K_C

= -2.303 x (8.314 mol^-1 K^-1) x 298 K x log 73

= -2.303 x 8.314 x 298 x 1.8633

= -10632 J = -10.632 kJ

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The equilibrium constant of the reactionCO2 (g) + H2 (g) ⇌ CO (g) + H2O (g) at 298 K is 73. Calculate the value of the standard free energy change, (Q = 8.314 J mol-1 K-1).

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