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The equilibrium constants for the reaction, `A_2hArr2A` A at `500K and 700K` are `1xx10^(-10)` and `1xx10^(-5)`. The given reaction isA. exothermicB. slowC. endothermicD. fast |
Answer» Correct Answer - B For the reaction. `A-2hArr2A` `K=([A])^2/([A_2])` The value of equilibrium constant is very less and hence, the product concentration is also very less. So, the reaction is slow. |
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