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The equilibrium constants of the following areA. `K_1K_(3)^(3)//K_2`B. `K_2K_(3)^(3)//K_1`C. `K_2K_(3)//K_1`D. `K_2^(3)K_(3)//K_1` |
Answer» Correct Answer - B Given, `N_2+3H_2hArr2NH_3,K_1` .....(1) `N_2+O_2hArr2NO,K_2` .....(ii) `H_2+(1)/(2)O_2toH_2O,K_2` .......(iii) To calculate , `2NH_3+(5)/(2)O_2overset(K)hArr2NO+3H_2O` `K=?` .....(iv) On reversing the equaiton (1) and multiplying the equation (iii) by 3, we get `2NH_3hArrN_2+3H_2,(1)/(K_1)` ....(v) `3H_2+(3)/(2)O_2to 3H_2O,K_(3)^(3)` ......(vi) Now, add equation (ii),(v) and (vi), we get the resultant equation (iv). `2NH_3+(5)/(2)O_2overset(K)hArr2NO+3H_2O` `K=(K_2K^2)/(K_1)` |
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