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The equilibrium : `PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))` shows that `K_(p) (atm)` is double to the value of `K_(c)` (`mol litre^(-1)`) at a particular temperature `T`, then `T` is :A. `2 K`B. `12.18 K`C. `24.36 K`D. `27.3 K` |
Answer» `(K_(p))/(K_(c))=(RT)^(Deltan)`, `:. 2=(0.0821xxT)^(1)` `:. T=24.36 K` |
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