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The equivalent capacitance of the combination between A and B in the given figure is 4 mu F. What will be the potential drop across each capacitor ? |
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Answer» Solution :If potential drops across the `20 mu F` and `5 mu F ` capacitors be `V_1` and `V_2` respectively , then `(V_(1))/(V_(2)) = (C_(2))/(C_(1)) = (5 mu F)/(20 mu F) = (1)/(4) implies V_(2) = 4 V_(1)` MOREOVER , `V_(1) + V_(2) = 12 V implies V_(1) = 2 .4 V ` and `V_(2) = 9.6 V ` |
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