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The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted toA. `Mn_(2)O_(3)`B. `MnO_(2)`C. `MnO_(4)^(ɵ)`D. `MnO_(4)^(2-)` |
Answer» Correct Answer - B `MnSO_(4)` `x+6-8=0, x=2` In (a) `Mn_(2)O_(3), 2x-6=0, x=3` in (b) `MnO_(2), x-4=0, x=4` In (c) `MnO_(4)^(ɵ), x-8=-1,x=7` In (d) `MnO_(4)^(2-), x-8=-2,x=6` In (b), the change in oxidation number is `4-2=2` Therefore, the answer is (b). |
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