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The equivalent weight of `Zn(OH)_(2)` is the following reaction is equal to its, `[Zn(OH)_(2)to(NO_(3))toZn(OH)(NO_(3))+H_(2)O]`A. `("Formula wt.")/(2)`B. `("Formula wt.")/(1)`C. `3xx`formulaD. `2xx`formula |
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Answer» Correct Answer - B Equivalent weight of `Zn(OH)_(2)=("Molecular weight")/("Acidicty")=(M)/(1)` |
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