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The equlibrium constant for the reaction `N_(2)+3H_(2)hArr2NH_(3)` is K, then the equlibrium constant for the equlibrium `NH_(3) 1/2N_(2)+3/2H_(2)` isA. `1//K`B. `1//K^(2)`C. `sqrtK`D. `(1)/(sqrtK)` |
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Answer» Correct Answer - D `K_(1)"for" N_(2)+3H_(2)hArr2NH_(3)` `K_(2)"for" NH_(3)hArr1/2N_(2)++3/2H_(2)` `K_(1)xxK_(2)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))xx([N_(2)]^(1//2)[H_(2)]^(3//2))/([NH_(3)])` `K_(1)xxK_(2)=(1)/(K_(2)),K_(2)=(1)/(sqrt(K_(1)))` |
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