The equlibrium constant is `6.0xx10^(-4)` for the `N_(2)+O_(2)hArr2NO` reaction. If the concentration of nitrogen is `0.10` mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equlibrium isA. `10.9xx10^(-3)mol//L`B. `1.09xx10^(-3)mol//L`C. `10.9xx10^(-5)mol//L`D. `1.09xx10^(-5)mol//L`

The equlibrium constant is `6.0xx10^(-4)` for the `N_(2)+O_(2)hArr2NO`

1.	The equlibrium constant is `6.0xx10^(-4)` for the `N_(2)+O_(2)hArr2NO` reaction. If the concentration of nitrogen is `0.10` mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equlibrium isA. `10.9xx10^(-3)mol//L`B. `1.09xx10^(-3)mol//L`C. `10.9xx10^(-5)mol//L`D. `1.09xx10^(-5)mol//L`
Answer» Correct Answer - B `K_(c)=([NO]^(2))/([N_(2)][O_(2)])` `6xx10^(-4)=([NO]^(2))/(0.10xx0.20` `[NO]=sqrt(6.0xx10^(-4)xx0.10xx0.20)` `=1.09xx10^(-3)mol//L`

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