The equlibrium constant `(K_(c))` for the reaction `HA+B hArrBH^(+)+A^(-)` is 100. If the rate constant for the forward reactio is `10^(5).` then rate constant for the backward reaction isA. `10^(7)`B. `10^(3)`C. `10^(-3)`D. `10^(-5)`

The equlibrium constant `(K_(c))` for the reaction `HA+B hArrBH^(+)+A^

1.	The equlibrium constant `(K_(c))` for the reaction `HA+B hArrBH^(+)+A^(-)` is 100. If the rate constant for the forward reactio is `10^(5).` then rate constant for the backward reaction isA. `10^(7)`B. `10^(3)`C. `10^(-3)`D. `10^(-5)`
Answer» Correct Answer - B `K_(c)(K_(f))/(K_(b))thereforeK_(b)=(K_(f))/(K_(c))=(10^(5))/(100)=100^(3)`

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The equlibrium constant `(K_(c))` for the reaction `HA+B hArrBH^(+)+A^(-)` is 100. If the rate constant for the forward reactio is `10^(5).` then rate constant for the backward reaction isA. `10^(7)`B. `10^(3)`C. `10^(-3)`D. `10^(-5)`

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