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The escape velocity for a body projected vertically upwards from the surface of earth is 11km/s. If the body is projected at an angle of `45^@` with the vertical, the escape velocity will beA. `11sqrt2km/s`B. 22km/sC. 11km/sD. `(11)/(sqrt2) km/s` |
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Answer» Correct Answer - C (c ) `V_e = sqrt(2gR)` The escape velocity is independent of the angle at which the body is projected. |
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