1.

The escape velocity for a planet is `v_e`. A particle starts from rest at a large distance from the planet, reaches the planet only under gravitational attraction, and passes through a smooth tunnel through its centre. Its speed at the centre of the planet will beA. `sqrt(1.5) v_(e)`B. `v_(e)/sqrt(2)`C. `v_(e)`D. zero

Answer» Correct Answer - A
From mechanical energy conservation, `0+0=1/2 mv^(2) - (3GMm)/(2R) implies v= sqrt((3GM)/R)=sqrt(1.5) v_(e)`.


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