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The escape velocity for a planet is `v_(e)`. A tunnel is dug along a diameter of the planet and a small body is dropped into it at the surface. When the body reaches the centre of the planet, its speed will beA. `v_(e )`B. `(v_(e ))/(sqrt(2))`C. `(v_(e ))/(2)`D. zero |
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Answer» Correct Answer - B From energy conservation Potential inside sphere `V=-(GM)/(2R^(3))(3R^(2)-r^(2))` `V_(s)=-(GM)/(R ), V_(0)=-(3GM)/(2R)` Loss of potential energy of partical = Gain of kinetic energy `m(V_(s)-V_(0))=(1)/(2)mv^(2)` `v^(2)=2[-(GM)/(R )(-(3GM)/(R ))]rArr v= sqrt((GM)/(R )) rArr v = sqrt((2GM)/(2R)) rArr v = (V_(e ))/(sqrt(2))` |
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