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The escape velocity form the earth is 11 `kms^(-1)` the esacpe velocity from a planet having twice the radius and the same mean denisty as the earth would beA. 5.5 `kms^(-1)`B. `11 kms(-1)`C. `15.5 kms^(-1)`D. `22 kms^(-1)` |
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Answer» Correct Answer - D Escape velocity `V_(e)=sqrt(2GM)/(R )` (here ,d = mean denisty of earth) now `v_(e ) prop Rsqrt(d)` `therefore (V_(e))/(v_(p))=(R_(e))/(R_(p))sqrt((d_(e))/(d_(p))=(R_(e))/(2R_(e))sqrt(d_(e))/(d_(e))` `v_(p)=2v_(e )=2xx11=232 kms^(-1)` |
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