1.

The escape Velocity from the earth is `11.2 Km//s`. The escape Velocity from a planet having twice the radius and the same mean density as the earth, is :A. 22.4 km/sB. 11.2 km/sC. 5.56 km/sD. 15.5 km/s

Answer» Correct Answer - a
`(v_(e_(2)))/(v_(e_(1)))=(R_(2))/(R_(1))sqrt((rho_(2))/(rho_(1)))=2`
`v_(e_(2))=2v_(e_(1))=2xx11.2=22.4km//s.`


Discussion

No Comment Found

Related InterviewSolutions