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The escape Velocity from the earth is `11.2 Km//s`. The escape Velocity from a planet having twice the radius and the same mean density as the earth, is :A. 22.4 km/sB. 11.2 km/sC. 5.56 km/sD. 15.5 km/s |
Answer» Correct Answer - a `(v_(e_(2)))/(v_(e_(1)))=(R_(2))/(R_(1))sqrt((rho_(2))/(rho_(1)))=2` `v_(e_(2))=2v_(e_(1))=2xx11.2=22.4km//s.` |
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