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The escape Velocity from the earth is `11.2 Km//s`. The escape Velocity from a planet having twice the radius and the same mean density as the earth, is :A. `11.2 km//s`B. `15.00 km//s`C. `22.4 km//s`D. `5.8 km//s` |
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Answer» Correct Answer - C Escape velocity, `v_(e)=sqrt((2GM_(E))/(R_(E)))` Also since earth is assumed spherical in shape its mass is given by `M=4/3 pi R^(3)xxrho` `:. v_(e)=sqrt((2G)/Rxx4/3piR^(3)rho)=Rsqrt(8/3 pi G rho)` ` :. v_(e) prop R` if `rho`=constant Since the planet having double radius in comparison to earth, therefore the escape velocity becomes twice, i.e. `22km//s ` |
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