1.

The escape velocity from the earth is `11 km//s`. The escape velocity from a planet having twice the radius and same density as that of the earth is (in `km//s`)A. 31 km/sB. 11 km/sC. 22 km/sD. 15.5 km/s

Answer» Correct Answer - a
`(v_(e_(2)))/(v_(e_(1)))=(R_(2))/(R_(1))sqrt((rho_(2))/(rho_(1)))=2sqrt2`
`v_(e_(1))=2sqrt2xx11`
`=22xx1.414="31.108km/s."`


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