1.

The escape velocity of a body from the earth is `11.2 km//s`. If a body is projected with a velocity twice its escape velocity, then the velocity of the body at infinity is (in `km//s`)A. `19.4`B. `194`C. `1.94`D. `0.194`

Answer» Correct Answer - A
Velocity at infinity
`v_(oo)=sqrt(v^(2)-v_(e)^(2))=sqrt([2(11.2)]^(2)-(11.2)^(2))`


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