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The escape velocity of a body from the earth is `V_(e)` if the radius of earth contracts to `1//4` th of its value keeping the mass of the earth constant the escape velocity will beA. doubledB. halvedC. tripledD. unaltered |
Answer» Correct Answer - A Escape velocity `V_(e)=sqrt(2GM)/(R ),R=(R )/(4)` opr `V_(e )=2 sqrt(2GM)/(R )` since G and M are constant hence `V_(e )=2v_(e )` |
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