1.

The escape velocity of a body from the surface of the earth is `V_(1)` and from an altitude equal to twice the radius of the earth, is, `V_(2)`. ThenA. `V_(1)=V_(2)`B. `V_(1)=7V_(2)`C. `V_(1)=sqrt(3)V_(2)`D. `V_(1)=sqrt(2)V_(2)`

Answer» Correct Answer - C
`1/2mv^(2)=(GmM)/((R+h))`,


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